x^2+12x-5=40

Solution for x^2+12x-5=40 equation:

Simplifying
x2 + 12x + -5 = 40

Reorder the terms:
-5 + 12x + x2 = 40

Solving
-5 + 12x + x2 = 40

Solving for variable 'x'.

Reorder the terms:
-5 + -40 + 12x + x2 = 40 + -40

Combine like terms: -5 + -40 = -45
-45 + 12x + x2 = 40 + -40

Combine like terms: 40 + -40 = 0
-45 + 12x + x2 = 0

Factor a trinomial.
(-15 + -1x)(3 + -1x) = 0

Subproblem 1
Set the factor '(-15 + -1x)' equal to zero and attempt to solve:

Simplifying
-15 + -1x = 0

Solving
-15 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + -1x = 0 + 15

Combine like terms: -15 + 15 = 0
0 + -1x = 0 + 15
-1x = 0 + 15

Combine like terms: 0 + 15 = 15
-1x = 15

Divide each side by '-1'.
x = -15

Simplifying
x = -15
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {-15, 3}